((x^2-3x+2)/(x^2+5x+6))*((x+2)/(4x-4))

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Solution for ((x^2-3x+2)/(x^2+5x+6))*((x+2)/(4x-4)) equation:


D( x )

x^2+5*x+6 = 0

4*x-4 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

4*x-4 = 0

4*x-4 = 0

4*x-4 = 0 // + 4

4*x = 4 // : 4

x = 4/4

x = 1

x in (-oo:-3) U (-3:-2) U (-2:1) U (1:+oo)

((x^2-(3*x)+2)/(x^2+5*x+6))*((x+2)/(4*x-4)) = 0

((x^2-3*x+2)/(x^2+5*x+6))*((x+2)/(4*x-4)) = 0

((x^2-3*x+2)*(x+2))/((x^2+5*x+6)*(4*x-4)) = 0

x^2-3*x+2 = 0

x^2-3*x+2 = 0

DELTA = (-3)^2-(1*2*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)+3)/(1*2) or x = (3-1^(1/2))/(1*2)

x = 2 or x = 1

(x-1)*(x-2) = 0

x^2+5*x+6 = 0

x^2+5*x+6 = 0

DELTA = 5^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)-5)/(1*2) or x = (-1^(1/2)-5)/(1*2)

x = -2 or x = -3

(x+3)*(x+2) = 0

((x-1)*(x-2))/((x+3)*(4*x-4)) = 0

( x-1 )

x-1 = 0 // + 1

x = 1

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 1}

x = 2

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